1230B - Ania and Minimizing - CodeForces Solution

greedy implementation *1000

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Python Code: 

n,k = list(map(int,input().split()))
s = list(input())
if n==1:
    if k==1:
        print(0)
    else:
        print("".join(s))
    
else:
    if s[0]!='1' and k>0:
        s[0]='1'
        k-=1
        
        
    for i in range(1,n):
        if s[i]!='0' and k>0:
            s[i]='0'
            k-=1 
    print("".join(s))

C++ Code: 

#include <bits/stdc++.h>

using namespace std;

main(){
	int n, k;
	cin >> n >> k;
	
	string s;
	cin >> s;
	
	if(n==1){
		if(k==1){
			cout << 0;		
		}else{
			cout << s;
		}
	}else{
		
		if(k>0 && s[0] != '1'){
			k--;
			s[0] = '1';
		}
		
		int i=1;
		while(i < n && k > 0){
			if(s[i] != '0'){
				s[i] = '0';
				k--;
			}		
			i++;
		}	
			
		
		cout << s;
	}
	
	
}


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